WithinPastHours
Check whether two TDateTimes are only a number of hours apart
Declaration
Source position: dateutil.inc line 247
function WithinPastHours(const ANow: TDateTime; const AThen: TDateTime;
const AHours: Int64) : Boolean;
Description
WithinPastHours compares the timestamps ANow and AThen and returns True if the difference between them is at most AHours hours apart, or False if they are further apart.
Remark
Since this function uses the HoursBetween function to calculate the difference in Hours, this means that fractional hours do not count, and the fractional part is simply dropped, so for two dates actually 2 and a half hours apart, the result will also be True !!!
See also
| Name | Description |
|---|---|
| WithinPastDays | Check whether two TDateTimes are only a number of days apart |
| WithinPastMilliSeconds | Check whether two TDateTimes are only a number of milliseconds apart |
| WithinPastMinutes | Check whether two TDateTimes are only a number of minutes apart |
| WithinPastMonths | Check whether two TDateTimes are only a number of months apart |
| WithinPastSeconds | Check whether two TDateTimes are only a number of seconds apart |
| WithinPastWeeks | Check whether two TDateTimes are only a number of weeks apart |
| WithinPastYears | Check whether two TDateTimes are only a number of years apart |
Example
Program Example51;
{ This program demonstrates the WithinPastHours function }
Uses SysUtils,DateUtils;
Procedure Test(ANow,AThen : TDateTime; AHours : Integer);
begin
Write(DateTimeToStr(AThen),' and ',DateTimeToStr(ANow));
Write(' are within ',AHours,' hours: ');
Writeln(WithinPastHours(ANow,AThen,AHours));
end;
Var
D1,D2 : TDateTime;
Begin
D1:=Now;
D2:=D1-(59*OneMinute);
Test(D1,D2,1);
D2:=D1-(61*OneMinute);
Test(D1,D2,1);
D2:=D1-(122*OneMinute);
Test(D1,D2,1);
D2:=D1-(306*OneMinute);
Test(D1,D2,5);
D2:=D1-(5.4*OneHour);
Test(D1,D2,5);
D2:=D1-(2.5*OneHour);
Test(D1,D2,1);
Test(D1,D2,2);
Test(D1,D2,3);
End.